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[Fixed] Element implicitly has an ‘any’ type because expression of type ‘string’ can’t be used to index in ReactJs

Today We are Going To Solve Element implicitly has an ‘any’ type because expression of type ‘string’ can’t be used to index in ReactJs in reactjs. Here we will Discuss All Possible Solutions and How this error Occurs So let’s get started with this Article.

How to Fix Element implicitly has an ‘any’ type because expression of type ‘string’ can’t be used to index in ReactJs Error?

  1. How to Fix Element implicitly has an ‘any’ type because expression of type ‘string’ can’t be used to index in ReactJs Error?

    To Fix Element implicitly has an ‘any’ type because expression of type ‘string’ can’t be used to index in ReactJs Error just Run the code. You can solve this error very easily. This method works when you are using Object.keys. So if you are using Object.keys then just use the given below code. And your error will be removed.
    Object.keys(this) .forEach(key => { console.log(this[key as keyof MyClass]); });

  2. Element implicitly has an ‘any’ type because expression of type ‘string’ can’t be used to index in ReactJs

    To Fix Element implicitly has an ‘any’ type because expression of type ‘string’ can’t be used to index in ReactJs Error just Use object.entries() and append(). Here I am just using this below code to solve my error with object.entries() and append() functions. So try this. Object.entries(data).forEach(item => { formData.append(item[0], item[1]); });

Solution 1 : Run the code

You can solve this error very easily. This method works when you are using Object.keys. So if you are using Object.keys then just use the given below code. And your error will be removed.

Object.keys(this)
    .forEach(key => {
      console.log(this[key as keyof MyClass]);
    });

Solution 2 : Use object.entries() and append()

Here I am just using this below code to solve my error with object.entries() and append() functions. So try this.

Object.entries(data).forEach(item => {
    formData.append(item[0], item[1]);
});

Conclusion

So these were all possible solutions to this error. I hope your error has been solved by this article. In the comments, tell us which solution worked? If you liked our article, please share it on your social media and comment on your suggestions. Thank you.

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